큰 txt파일을 읽으면 메모리 문제 발생하기때문에 분할해서 단어장 처리. 

import os
import sys
import konlpy
import pandas as pd
import numpy as np
os.environ['JAVA_OPTS'] = 'Xmx4096M'

import itertools

import mr #local module

file_name = "test_export_mentions_2020-11-17_title.txt"
#file_name = "test_export_mentions_2020-11-17_title_utf8.txt"  #test
file_out  = "outputfile"
lines_tot = mr.file_len(file_name)
filesize  = mr.getfilesize(file_name) * 1000
print("파일명 : ", file_name)
print("줄 개수 : ", lines_tot)
print("파일사이즈 : ", filesize)

f = open(file_name,'r', encoding='utf-8')
numbits  = 1000000
loop_num = round(os.stat(file_name).st_size/numbits+1)+1

print(os.stat(file_name).st_size/numbits+1)
print(loop_num)

for i in range(0, loop_num):
    o = open('./input/'+file_out+str(i)+'.txt','w', encoding='utf-8')
    segment = f.readlines(numbits)
    for c in range(0,len(segment)):
        o.write(segment[c]+"\n")
    o.close()


 

import itertools

def f_append(text):
    sign = 'N'
    #기존 파일의 단어를 가져와서 신규 단어가 있는지 확인
    with open('./replace_word.txt','r',encoding='utf-8') as f:
        list_word = f.read().strip().split('\n')
        for line in list_word:
            if line == text:
                sign = 'Exist'
                #print('Exist')
        '''
        list_word = f.read()
        if list_word.find(text) >=0:
            sign = 'N'
            print('Exist')
        '''
    if sign == 'N':
        #기존 파일에 단어추가
        with open('./replace_word.txt', 'a', encoding='utf-8') as myfile:
            myfile.write(text)
            myfile.write('\n')
            sign = 'Yes'

    return sign

def f_list():
    #단어파일을 list로 리턴
    with open('./replace_word.txt','r',encoding='utf-8') as f:
        list_word = f.read().strip().split('\n')
    return list_word

def f_del(text):
    #입력받은 단어를 삭제
    sign = 'N'
    matrix = []
    with open('./replace_word.txt','r',encoding='utf-8') as f:
        dic = f.read().strip().split('\n')

    for word in dic:
        if word != text:
            matrix.append(word)
        else:
            sign = 'Del';
    print(sign)
    print(dic)

    if sign == 'Del':
        with open('./replace_word.txt', 'w', encoding='utf-8') as myfile:
            #myfile.write(matrix)
            for line2 in matrix:
                print(line2)
                myfile.write(line2)
                myfile.write('\n')
            sign = 'Y'

    return sign

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Despite being over 23 years old, the PSD file format is still extremely opaque. PSD.rb is a Ruby library for reading and writing PSDs that means you don’t have to know how the file format works in order to use it.