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Remove Elements From A Counter

 

counter에서 요소 삭제하기

Question:

How do you remove an element from a counter?

Answer:

Setting a count to zero does not remove an element from a counter. Use del to remove it entirely.

Source: (example.py)

from collections import Counter
 
c = Counter(x=10, y=7, z=3)
print(c)
 
c['z'] = 0
print(c)
 
del c['z']
print(c)

Output:

$ python example.py
Counter({'x': 10, 'y': 7, 'z': 3})
Counter({'x': 10, 'y': 7, 'z': 0})
Counter({'x': 10, 'y': 7})
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텍스트로 요소 찾기

 

jQuery: find element by text

Can anyone tell me if it's possible to find an element based on its content rather than by an id or class? I am attempting to find elements that don't have distinct classes or id's. (Then I then n...

stackoverflow.com

ID  클래스가 아닌 내용을 기반으로 요소를 찾을 수 있는지 누구든지 말할 수 있습니까 ?

고유 한 클래스 나 ID가없는 요소를 찾으려고합니다. (그런 다음 해당 요소의 부모를 찾아야합니다.)

 

Therefore it is not enough that you use :contains() selector, you also need to check if the text you search for is the direct content of the element you are targeting for, something like that:

따라서 :contains() selector 를 사용하는 것으로는 충분하지 않습니다. 검색하는 텍스트 가 대상 요소  직접 콘텐츠 인지 확인해야 합니다.

 

 

 Element에 포함된 텍스트(Text)로 객체를 찾아라!

function findElementByText(text) {
    var jSpot = $("b:contains(" + text + ")")
                .filter(function() { return $(this).children().length === 0;})
                .parent();  // because you asked the parent of that element

    return jSpot;
}

 * 아래 DIV   p-1 class 중에 텍스트가 3인 것을 찾아라. 

<div class="" id="pagenation" style="white-space: nowrap; overflow-x: hidden; width: 231px;">
<div class="p-1 paging-item border rounded text-center d-inline-block position-relative" style="width:33px;height:33px;">1</div>
<div class="p-1 paging-item border rounded text-center d-inline-block position-relative" style="width:33px;height:33px;">2</div>
<div class="p-1 paging-item border rounded text-center d-inline-block position-relative  style="width:33px;height:33px;">3</div>
<div class="p-1 paging-item border rounded text-center d-inline-block position-relative" style="width:33px;height:33px;">4</div>
<div class="p-1 paging-item border rounded text-center d-inline-block position-relative" style="width:33px;height:33px;">5</div><div class="p-1 paging-item border rounded text-center d-inline-block position-relative" style="width:33px;height:33px;">6</div><div class="p-1 paging-item border rounded text-center d-inline-block position-relative" style="width:33px;height:33px;">7</div>
</div>


$(".p-1:contains('3')")
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jQuery 데이터 속성 값을 기반으로 요소를 찾는 방법은 무엇입니까?

jQuery how to find an element based on a data-attribute value?

 

jQuery how to find an element based on a data-attribute value?

I've got the following scenario: var el = 'li'; and there are 5

  • 's on the page each with a data-slide=number attribute (number being 1,2,3,4,5 respectively). I now need to find the cur...

     

    stackoverflow.com

I've got the following scenario:

var el = 'li';

and there are 5 <li>'s on the page each with a data-slide=number attribute (number being 1,2,3,4,5 respectively).

I now need to find the currently active slide number which is mapped to var current = $('ul').data(current); and is updated on each slide change.

So far my tries have been unsuccessful, trying to construct the selector that would match the current slide:

$('ul').find(el+[data-slide=+current+]);

does not match/return anything…

The reason I can't hardcode the li part is that this is a user accessible variable that can be changed to a different element if required, so it may not always be an li.

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jQuery 에서 해당 요소(element)의 존재여부를 확인할 때


length로 길이를 확인해서 처리하면 된다.


//This will not work
if ( $("#myid") ) {
//do something
}


아래와 같이 해야 확인이 가능하다.



if ( $("#myid").length > 0 ) {
//do something
}

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